4cos(2x)+4=-sin(8y)

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Solution for 4cos(2x)+4=-sin(8y) equation:


Simplifying
4cos(2x) + 4 = -1sin(8y)

Remove parenthesis around (2x)
4cos * 2x + 4 = -1sin(8y)

Reorder the terms for easier multiplication:
4 * 2cos * x + 4 = -1sin(8y)

Multiply 4 * 2
8cos * x + 4 = -1sin(8y)

Multiply cos * x
8cosx + 4 = -1sin(8y)

Reorder the terms:
4 + 8cosx = -1sin(8y)

Remove parenthesis around (8y)
4 + 8cosx = -1ins * 8y

Reorder the terms for easier multiplication:
4 + 8cosx = -1 * 8ins * y

Multiply -1 * 8
4 + 8cosx = -8ins * y

Multiply ins * y
4 + 8cosx = -8insy

Solving
4 + 8cosx = -8insy

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 8cosx = -4 + -8insy

Combine like terms: 4 + -4 = 0
0 + 8cosx = -4 + -8insy
8cosx = -4 + -8insy

Divide each side by '8osx'.
c = -0.5o-1s-1x-1 + -1ino-1x-1y

Simplifying
c = -0.5o-1s-1x-1 + -1ino-1x-1y

Reorder the terms:
c = -1ino-1x-1y + -0.5o-1s-1x-1

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