4d+14=3(d-1)

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Solution for 4d+14=3(d-1) equation: 



4d+14=3(d-1)

We move all terms to the left:

4d+14-(3(d-1))=0



We calculate terms in parentheses: -(3(d-1)), so:

3(d-1)

We multiply parentheses

3d-3

Back to the equation:

-(3d-3)



We get rid of parentheses

4d-3d+3+14=0

We add all the numbers together, and all the variables

d+17=0

We move all terms containing d to the left, all other terms to the right

d=-17

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