4d+3(d-4)=-3(d+12)

Solution for 4d+3(d-4)=-3(d+12) equation:

4d+3(d-4)=-3(d+12)

We move all terms to the left:

4d+3(d-4)-(-3(d+12))=0

We multiply parentheses

4d+3d-(-3(d+12))-12=0


We calculate terms in parentheses: -(-3(d+12)), so:

-3(d+12)

We multiply parentheses

-3d-36

Back to the equation:

-(-3d-36)


We add all the numbers together, and all the variables

7d-(-3d-36)-12=0

We get rid of parentheses

7d+3d+36-12=0

We add all the numbers together, and all the variables

10d+24=0

We move all terms containing d to the left, all other terms to the right

10d=-24

d=-24/10

d=-2+2/5