4d+5(7d-3)=9(d-5)

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Solution for 4d+5(7d-3)=9(d-5) equation: 



4d+5(7d-3)=9(d-5)

We move all terms to the left:

4d+5(7d-3)-(9(d-5))=0

We multiply parentheses

4d+35d-(9(d-5))-15=0



We calculate terms in parentheses: -(9(d-5)), so:

9(d-5)

We multiply parentheses

9d-45

Back to the equation:

-(9d-45)



We add all the numbers together, and all the variables

39d-(9d-45)-15=0

We get rid of parentheses

39d-9d+45-15=0

We add all the numbers together, and all the variables

30d+30=0

We move all terms containing d to the left, all other terms to the right

30d=-30

d=-30/30

d=-1

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