4d+5(7d-3)=9(d-5)

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Solution for 4d+5(7d-3)=9(d-5) equation:



4d+5(7d-3)=9(d-5)
We move all terms to the left:
4d+5(7d-3)-(9(d-5))=0
We multiply parentheses
4d+35d-(9(d-5))-15=0
We calculate terms in parentheses: -(9(d-5)), so:
9(d-5)
We multiply parentheses
9d-45
Back to the equation:
-(9d-45)
We add all the numbers together, and all the variables
39d-(9d-45)-15=0
We get rid of parentheses
39d-9d+45-15=0
We add all the numbers together, and all the variables
30d+30=0
We move all terms containing d to the left, all other terms to the right
30d=-30
d=-30/30
d=-1

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