4d-5(d-1)=3-d+2

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Solution for 4d-5(d-1)=3-d+2 equation:


Simplifying
4d + -5(d + -1) = 3 + -1d + 2

Reorder the terms:
4d + -5(-1 + d) = 3 + -1d + 2
4d + (-1 * -5 + d * -5) = 3 + -1d + 2
4d + (5 + -5d) = 3 + -1d + 2

Reorder the terms:
5 + 4d + -5d = 3 + -1d + 2

Combine like terms: 4d + -5d = -1d
5 + -1d = 3 + -1d + 2

Reorder the terms:
5 + -1d = 3 + 2 + -1d

Combine like terms: 3 + 2 = 5
5 + -1d = 5 + -1d

Add '-5' to each side of the equation.
5 + -5 + -1d = 5 + -5 + -1d

Combine like terms: 5 + -5 = 0
0 + -1d = 5 + -5 + -1d
-1d = 5 + -5 + -1d

Combine like terms: 5 + -5 = 0
-1d = 0 + -1d
-1d = -1d

Add 'd' to each side of the equation.
-1d + d = -1d + d

Combine like terms: -1d + d = 0
0 = -1d + d

Combine like terms: -1d + d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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