4e+2(-11+e)-4=8(3+e)+2(.5+6e)+19

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Solution for 4e+2(-11+e)-4=8(3+e)+2(.5+6e)+19 equation: 



4e+2(-11+e)-4=8(3+e)+2(.5+6e)+19

We move all terms to the left:

4e+2(-11+e)-4-(8(3+e)+2(.5+6e)+19)=0

We add all the numbers together, and all the variables

4e+2(e-11)-(8(e+3)+2(6e+0.5)+19)-4=0

We multiply parentheses

4e+2e-(8(e+3)+2(6e+0.5)+19)-22-4=0



We calculate terms in parentheses: -(8(e+3)+2(6e+0.5)+19), so:

8(e+3)+2(6e+0.5)+19

We multiply parentheses

8e+12e+24+1+19

We add all the numbers together, and all the variables

20e+44

Back to the equation:

-(20e+44)



We add all the numbers together, and all the variables

6e-(20e+44)-26=0

We get rid of parentheses

6e-20e-44-26=0

We add all the numbers together, and all the variables

-14e-70=0

We move all terms containing e to the left, all other terms to the right

-14e=70

e=70/-14

e=-5

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