4e-19=3(e+12)

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Solution for 4e-19=3(e+12) equation: 



4e-19=3(e+12)

We move all terms to the left:

4e-19-(3(e+12))=0



We calculate terms in parentheses: -(3(e+12)), so:

3(e+12)

We multiply parentheses

3e+36

Back to the equation:

-(3e+36)



We get rid of parentheses

4e-3e-36-19=0

We add all the numbers together, and all the variables

e-55=0

We move all terms containing e to the left, all other terms to the right

e=55

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