4f+22-2f=6(f+1)

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Solution for 4f+22-2f=6(f+1) equation: 



4f+22-2f=6(f+1)

We move all terms to the left:

4f+22-2f-(6(f+1))=0

We add all the numbers together, and all the variables

2f-(6(f+1))+22=0



We calculate terms in parentheses: -(6(f+1)), so:

6(f+1)

We multiply parentheses

6f+6

Back to the equation:

-(6f+6)



We get rid of parentheses

2f-6f-6+22=0

We add all the numbers together, and all the variables

-4f+16=0

We move all terms containing f to the left, all other terms to the right

-4f=-16

f=-16/-4

f=+4

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