4f+3(2f-3)=27

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Solution for 4f+3(2f-3)=27 equation: 



4f+3(2f-3)=27

We move all terms to the left:

4f+3(2f-3)-(27)=0

We multiply parentheses

4f+6f-9-27=0

We add all the numbers together, and all the variables

10f-36=0

We move all terms containing f to the left, all other terms to the right

10f=36

f=36/10

f=3+3/5

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