4f=2(f-5)-2

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Solution for 4f=2(f-5)-2 equation: 



4f=2(f-5)-2

We move all terms to the left:

4f-(2(f-5)-2)=0



We calculate terms in parentheses: -(2(f-5)-2), so:

2(f-5)-2

We multiply parentheses

2f-10-2

We add all the numbers together, and all the variables

2f-12

Back to the equation:

-(2f-12)



We get rid of parentheses

4f-2f+12=0

We add all the numbers together, and all the variables

2f+12=0

We move all terms containing f to the left, all other terms to the right

2f=-12

f=-12/2

f=-6

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