4g+(7g-3)=9(g-5)

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Solution for 4g+(7g-3)=9(g-5) equation: 



4g+(7g-3)=9(g-5)

We move all terms to the left:

4g+(7g-3)-(9(g-5))=0

We get rid of parentheses

4g+7g-(9(g-5))-3=0



We calculate terms in parentheses: -(9(g-5)), so:

9(g-5)

We multiply parentheses

9g-45

Back to the equation:

-(9g-45)



We add all the numbers together, and all the variables

11g-(9g-45)-3=0

We get rid of parentheses

11g-9g+45-3=0

We add all the numbers together, and all the variables

2g+42=0

We move all terms containing g to the left, all other terms to the right

2g=-42

g=-42/2

g=-21

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