4g+2(-4+2g)=1+g

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Solution for 4g+2(-4+2g)=1+g equation: 



4g+2(-4+2g)=1+g

We move all terms to the left:

4g+2(-4+2g)-(1+g)=0

We add all the numbers together, and all the variables

4g+2(2g-4)-(g+1)=0

We multiply parentheses

4g+4g-(g+1)-8=0

We get rid of parentheses

4g+4g-g-1-8=0

We add all the numbers together, and all the variables

7g-9=0

We move all terms containing g to the left, all other terms to the right

7g=9

g=9/7

g=1+2/7

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