4g+5=4/g

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Solution for 4g+5=4/g equation: 


D( g )

g = 0

g = 0

g = 0

g in (-oo:0) U (0:+oo)

4*g+5 = 4/g // - 4/g

4*g-(4/g)+5 = 0

4*g-4*g^-1+5 = 0

4*g^1-4*g^-1+5*g^0 = 0

(4*g^2+5*g^1-4*g^0)/(g^1) = 0 // * g^2

g^1*(4*g^2+5*g^1-4*g^0) = 0

g^1

4*g^2+5*g-4 = 0

4*g^2+5*g-4 = 0

DELTA = 5^2-(-4*4*4)

DELTA = 89

DELTA > 0

g = (89^(1/2)-5)/(2*4) or g = (-89^(1/2)-5)/(2*4)

g = (89^(1/2)-5)/8 or g = (-(89^(1/2)+5))/8

g in { (-(89^(1/2)+5))/8, (89^(1/2)-5)/8} 

g in { (-(89^(1/2)+5))/8, (89^(1/2)-5)/8 }

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