4g+6+2g=3(2g+2)

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Solution for 4g+6+2g=3(2g+2) equation: 



4g+6+2g=3(2g+2)

We move all terms to the left:

4g+6+2g-(3(2g+2))=0

We add all the numbers together, and all the variables

6g-(3(2g+2))+6=0



We calculate terms in parentheses: -(3(2g+2)), so:

3(2g+2)

We multiply parentheses

6g+6

Back to the equation:

-(6g+6)



We get rid of parentheses

6g-6g-6+6=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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