4g-3(g-2)=-5(g-4)-g-26

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Solution for 4g-3(g-2)=-5(g-4)-g-26 equation: 



4g-3(g-2)=-5(g-4)-g-26

We move all terms to the left:

4g-3(g-2)-(-5(g-4)-g-26)=0

We multiply parentheses

4g-3g-(-5(g-4)-g-26)+6=0



We calculate terms in parentheses: -(-5(g-4)-g-26), so:

-5(g-4)-g-26

We add all the numbers together, and all the variables

-1g-5(g-4)-26

We multiply parentheses

-1g-5g+20-26

We add all the numbers together, and all the variables

-6g-6

Back to the equation:

-(-6g-6)



We add all the numbers together, and all the variables

g-(-6g-6)+6=0

We get rid of parentheses

g+6g+6+6=0

We add all the numbers together, and all the variables

7g+12=0

We move all terms containing g to the left, all other terms to the right

7g=-12

g=-12/7

g=-1+5/7

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