4g2-7g+g2-10g=

Solution for 4g2-7g+g2-10g= equation:

4g^2-7g+g2-10g=

We move all terms to the left:

4g^2-7g+g2-10g-()=0

We add all the numbers together, and all the variables

5g^2-17g=0

a = 5; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·5·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*5}=\frac{0}{10}
=0
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*5}=\frac{34}{10}
=3+2/5
$