4h(3h+8)=0

Solution for 4h(3h+8)=0 equation:

4h(3h+8)=0

We multiply parentheses

12h^2+32h=0

a = 12; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·12·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*12}=\frac{-64}{24}
=-2+2/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*12}=\frac{0}{24}
=0
$