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4h+2(h-5)=3(2h-4)
We move all terms to the left:
4h+2(h-5)-(3(2h-4))=0
We multiply parentheses
4h+2h-(3(2h-4))-10=0
We calculate terms in parentheses: -(3(2h-4)), so:We add all the numbers together, and all the variables
3(2h-4)
We multiply parentheses
6h-12
Back to the equation:
-(6h-12)
6h-(6h-12)-10=0
We get rid of parentheses
6h-6h+12-10=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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