4h+3(h-8)=2(3h-12)+h

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Solution for 4h+3(h-8)=2(3h-12)+h equation: 



4h+3(h-8)=2(3h-12)+h

We move all terms to the left:

4h+3(h-8)-(2(3h-12)+h)=0

We multiply parentheses

4h+3h-(2(3h-12)+h)-24=0



We calculate terms in parentheses: -(2(3h-12)+h), so:

2(3h-12)+h

We add all the numbers together, and all the variables

h+2(3h-12)

We multiply parentheses

h+6h-24

We add all the numbers together, and all the variables

7h-24

Back to the equation:

-(7h-24)



We add all the numbers together, and all the variables

7h-(7h-24)-24=0

We get rid of parentheses

7h-7h+24-24=0

We add all the numbers together, and all the variables

=0

h=0/1

h=0

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