4h-(3h-12)=-1/4(28h-16)

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Solution for 4h-(3h-12)=-1/4(28h-16) equation: 



4h-(3h-12)=-1/4(28h-16)

We move all terms to the left:

4h-(3h-12)-(-1/4(28h-16))=0



Domain of the equation: 4(28h-16))!=0

h∈R



We get rid of parentheses

4h-3h-(-1/4(28h-16))+12=0

We multiply all the terms by the denominator


4h*4(28h-16))-3h*4(28h-16))-(-1+12*4(28h-16))=0

We add all the numbers together, and all the variables

4h*4(28h-16))-3h*4(28h-16))-(-1+12*4(28h=0

Wy multiply elements

64h^3(2-16))-(+12*4(28h-1=0

We do not support ehpression: h^3(2

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