4h2+37h+9=0

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Solution for 4h2+37h+9=0 equation:



4h^2+37h+9=0
a = 4; b = 37; c = +9;
Δ = b2-4ac
Δ = 372-4·4·9
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-35}{2*4}=\frac{-72}{8} =-9 $
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+35}{2*4}=\frac{-2}{8} =-1/4 $

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