4h=2(h-5)-2

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Solution for 4h=2(h-5)-2 equation: 



4h=2(h-5)-2

We move all terms to the left:

4h-(2(h-5)-2)=0



We calculate terms in parentheses: -(2(h-5)-2), so:

2(h-5)-2

We multiply parentheses

2h-10-2

We add all the numbers together, and all the variables

2h-12

Back to the equation:

-(2h-12)



We get rid of parentheses

4h-2h+12=0

We add all the numbers together, and all the variables

2h+12=0

We move all terms containing h to the left, all other terms to the right

2h=-12

h=-12/2

h=-6

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