4i(8-7i)=0

Solution for 4i(8-7i)=0 equation:

4i(8-7i)=0

We add all the numbers together, and all the variables

4i(-7i+8)=0

We multiply parentheses

-28i^2+32i=0

a = -28; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-28)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-28}=\frac{-64}{-56}
=1+1/7
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-28}=\frac{0}{-56}
=0
$