4i+2(3i-2)=10

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Solution for 4i+2(3i-2)=10 equation: 



4i+2(3i-2)=10

We move all terms to the left:

4i+2(3i-2)-(10)=0

We multiply parentheses

4i+6i-4-10=0

We add all the numbers together, and all the variables

10i-14=0

We move all terms containing i to the left, all other terms to the right

10i=14

i=14/10

i=1+2/5

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