4j*8j=24

Solution for 4j*8j=24 equation:

4j*8j=24

We move all terms to the left:

4j*8j-(24)=0

Wy multiply elements

32j^2-24=0

a = 32; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·32·(-24)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*32}=\frac{0-32\sqrt{3}}{64}
=-\frac{32\sqrt{3}}{64}
=-\frac{\sqrt{3}}{2}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*32}=\frac{0+32\sqrt{3}}{64}
=\frac{32\sqrt{3}}{64}
=\frac{\sqrt{3}}{2}
$