4j-2=3(1/2j+2

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Solution for 4j-2=3(1/2j+2 equation: 



4j-2=3(1/2j+2

We move all terms to the left:

4j-2-(3(1/2j+2)=0



Domain of the equation: 2j+2)-2!=0

j∈R



We multiply all the terms by the denominator


4j*2j+2)-2-(3(1=0

We add all the numbers together, and all the variables

4j*2j=0

Wy multiply elements

8j^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$j=\frac{-b}{2a}=\frac{0}{16}=0$

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