4j2-2156=0

Solution for 4j2-2156=0 equation:

4j^2-2156=0

a = 4; b = 0; c = -2156;
Δ = b2-4ac
Δ = 02-4·4·(-2156)
Δ = 34496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34496}=\sqrt{3136*11}=\sqrt{3136}*\sqrt{11}=56\sqrt{11}$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{11}}{2*4}=\frac{0-56\sqrt{11}}{8}
=-\frac{56\sqrt{11}}{8}
=-7\sqrt{11}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{11}}{2*4}=\frac{0+56\sqrt{11}}{8}
=\frac{56\sqrt{11}}{8}
=7\sqrt{11}
$