4j2=144

Solution for 4j2=144 equation:

4j^2=144

We move all terms to the left:

4j^2-(144)=0

a = 4; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·4·(-144)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*4}=\frac{-48}{8}
=-6
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*4}=\frac{48}{8}
=6
$