4k(k-6)=6(k-12)

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Solution for 4k(k-6)=6(k-12) equation: 



4k(k-6)=6(k-12)

We move all terms to the left:

4k(k-6)-(6(k-12))=0

We multiply parentheses

4k^2-24k-(6(k-12))=0



We calculate terms in parentheses: -(6(k-12)), so:

6(k-12)

We multiply parentheses

6k-72

Back to the equation:

-(6k-72)



We get rid of parentheses

4k^2-24k-6k+72=0

We add all the numbers together, and all the variables

4k^2-30k+72=0

a = 4; b = -30; c = +72;
Δ = b2-4ac
Δ = -302-4·4·72
Δ = -252
Delta is less than zero, so there is no solution for the equation

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