4k+2/k=2

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Solution for 4k+2/k=2 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

4*k+2/k = 2 // - 2

4*k+2/k-2 = 0

4*k^1+2*k^-1-2*k^0 = 0

(4*k^2-2*k^1+2*k^0)/(k^1) = 0 // * k^2

k^1*(4*k^2-2*k^1+2*k^0) = 0

k^1

4*k^2-2*k+2 = 0

4*k^2-2*k+2 = 0

DELTA = (-2)^2-(2*4*4)

DELTA = -28

DELTA < 0

k in { } 

k belongs to the empty set

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