4k+3k-2=2(5-k)+6

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Solution for 4k+3k-2=2(5-k)+6 equation: 



4k+3k-2=2(5-k)+6

We move all terms to the left:

4k+3k-2-(2(5-k)+6)=0

We add all the numbers together, and all the variables

4k+3k-(2(-1k+5)+6)-2=0

We add all the numbers together, and all the variables

7k-(2(-1k+5)+6)-2=0



We calculate terms in parentheses: -(2(-1k+5)+6), so:

2(-1k+5)+6

We multiply parentheses

-2k+10+6

We add all the numbers together, and all the variables

-2k+16

Back to the equation:

-(-2k+16)



We get rid of parentheses

7k+2k-16-2=0

We add all the numbers together, and all the variables

9k-18=0

We move all terms containing k to the left, all other terms to the right

9k=18

k=18/9

k=2

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