4k+5-(3k+2)=6k-4-(4k-5)

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Solution for 4k+5-(3k+2)=6k-4-(4k-5) equation: 



4k+5-(3k+2)=6k-4-(4k-5)

We move all terms to the left:

4k+5-(3k+2)-(6k-4-(4k-5))=0

We get rid of parentheses

4k-3k-(6k-4-(4k-5))-2+5=0



We calculate terms in parentheses: -(6k-4-(4k-5)), so:

6k-4-(4k-5)

determiningTheFunctionDomain
6k-(4k-5)-4

We get rid of parentheses

6k-4k+5-4

We add all the numbers together, and all the variables

2k+1

Back to the equation:

-(2k+1)



We add all the numbers together, and all the variables

k-(2k+1)+3=0

We get rid of parentheses

k-2k-1+3=0

We add all the numbers together, and all the variables

-1k+2=0

We move all terms containing k to the left, all other terms to the right

-k=-2

k=-2/-1

k=+2

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