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4k-(3+k)=-(2+3k)
We move all terms to the left:
4k-(3+k)-(-(2+3k))=0
We add all the numbers together, and all the variables
4k-(k+3)-(-(3k+2))=0
We get rid of parentheses
4k-k-(-(3k+2))-3=0
We calculate terms in parentheses: -(-(3k+2)), so:We add all the numbers together, and all the variables
-(3k+2)
We get rid of parentheses
-3k-2
Back to the equation:
-(-3k-2)
3k-(-3k-2)-3=0
We get rid of parentheses
3k+3k+2-3=0
We add all the numbers together, and all the variables
6k-1=0
We move all terms containing k to the left, all other terms to the right
6k=1
k=1/6
k=1/6
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