4k-(3k-18)=2k

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Solution for 4k-(3k-18)=2k equation: 



4k-(3k-18)=2k

We move all terms to the left:

4k-(3k-18)-(2k)=0

We add all the numbers together, and all the variables

2k-(3k-18)=0

We get rid of parentheses

2k-3k+18=0

We add all the numbers together, and all the variables

-1k+18=0

We move all terms containing k to the left, all other terms to the right

-k=-18

k=-18/-1

k=+18

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