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4k-10/k=10
We move all terms to the left:
4k-10/k-(10)=0
Domain of the equation: k!=0We multiply all the terms by the denominator
k∈R
4k*k-10*k-10=0
We add all the numbers together, and all the variables
-10k+4k*k-10=0
Wy multiply elements
4k^2-10k-10=0
a = 4; b = -10; c = -10;
Δ = b2-4ac
Δ = -102-4·4·(-10)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{65}}{2*4}=\frac{10-2\sqrt{65}}{8} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{65}}{2*4}=\frac{10+2\sqrt{65}}{8} $
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