4k-12=2-(2k-6)

Solution for 4k-12=2-(2k-6) equation:

4k-12=2-(2k-6)

We move all terms to the left:

4k-12-(2-(2k-6))=0


We calculate terms in parentheses: -(2-(2k-6)), so:

2-(2k-6)

determiningTheFunctionDomain
-(2k-6)+2

We get rid of parentheses

-2k+6+2

We add all the numbers together, and all the variables

-2k+8

Back to the equation:

-(-2k+8)


We get rid of parentheses

4k+2k-8-12=0

We add all the numbers together, and all the variables

6k-20=0

We move all terms containing k to the left, all other terms to the right

6k=20

k=20/6

k=3+1/3