4k-12=5-4(k-12)

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Solution for 4k-12=5-4(k-12) equation: 



4k-12=5-4(k-12)

We move all terms to the left:

4k-12-(5-4(k-12))=0



We calculate terms in parentheses: -(5-4(k-12)), so:

5-4(k-12)

determiningTheFunctionDomain
-4(k-12)+5

We multiply parentheses

-4k+48+5

We add all the numbers together, and all the variables

-4k+53

Back to the equation:

-(-4k+53)



We get rid of parentheses

4k+4k-53-12=0

We add all the numbers together, and all the variables

8k-65=0

We move all terms containing k to the left, all other terms to the right

8k=65

k=65/8

k=8+1/8

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