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4k-4-3k=1/3(3k-12)
We move all terms to the left:
4k-4-3k-(1/3(3k-12))=0
Domain of the equation: 3(3k-12))!=0We add all the numbers together, and all the variables
k∈R
k-(1/3(3k-12))-4=0
We multiply all the terms by the denominator
k*3(3k-12))-(1-4*3(3k-12))=0
Wy multiply elements
3k^2(3-12k(3=0
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