4k-5=2(2k-3)+1

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Solution for 4k-5=2(2k-3)+1 equation:



4k-5=2(2k-3)+1
We move all terms to the left:
4k-5-(2(2k-3)+1)=0
We calculate terms in parentheses: -(2(2k-3)+1), so:
2(2k-3)+1
We multiply parentheses
4k-6+1
We add all the numbers together, and all the variables
4k-5
Back to the equation:
-(4k-5)
We get rid of parentheses
4k-4k+5-5=0
We add all the numbers together, and all the variables
=0
k=0/1
k=0

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