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4k^2-24k+20=0
a = 4; b = -24; c = +20;
Δ = b2-4ac
Δ = -242-4·4·20
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16}{2*4}=\frac{8}{8} =1 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16}{2*4}=\frac{40}{8} =5 $
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