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4k^2-28k=-49
We move all terms to the left:
4k^2-28k-(-49)=0
We add all the numbers together, and all the variables
4k^2-28k+49=0
a = 4; b = -28; c = +49;
Δ = b2-4ac
Δ = -282-4·4·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{28}{8}=3+1/2$
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