4ln(1/x)=1

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Solution for 4ln(1/x)=1 equation:


D( x )

x = 0

1/x <= 0

x = 0

x = 0

1/x <= 0

1/x <= 0

1*x^-1 <= 0

1*x^-1 <= 0 // : 1

x^-1 <= 0/1

x^-1 <= 0

1/(x^1) <= 0

x <> 0

1/(x^1) <= 0 // * x^2

(x^2)/(x^1) <= 0

x^1 <= 0

x <= 0

x in (-oo:0)

x in (0:+oo)

4*ln(1/x) = 1 // - 1

4*ln(1/x)-1 = 0

4*ln(1/x)-1 = 0 // + 1

4*ln(1/x) = 1 // : 4

ln(1/x) = 1/4

ln(1/x) = ln(e^(1/4))

1/x = e^(1/4)

1/x-e^(1/4) = 0

1*x^-1 = e^(1/4) // : 1

x^-1 = e^(1/4)

-1 < 0

1/(x^1) = e^(1/4) // * x^1

1 = e^(1/4)*x^1 // : e^(1/4)

1/(e^(1/4)) = x^1

x = 1/(e^(1/4))

x = 1/(e^(1/4))

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