4log(2x+1)=12

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Solution for 4log(2x+1)=12 equation:


Simplifying
4log(2x + 1) = 12

Reorder the terms:
4glo(1 + 2x) = 12
(1 * 4glo + 2x * 4glo) = 12
(4glo + 8glox) = 12

Solving
4glo + 8glox = 12

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-12 + 4glo + 8glox = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 4glo + 8glox = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-3 + glo + 2glox) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-3 + glo + 2glox)' equal to zero and attempt to solve: Simplifying -3 + glo + 2glox = 0 Solving -3 + glo + 2glox = 0 Move all terms containing g to the left, all other terms to the right. Add '3' to each side of the equation. -3 + glo + 3 + 2glox = 0 + 3 Reorder the terms: -3 + 3 + glo + 2glox = 0 + 3 Combine like terms: -3 + 3 = 0 0 + glo + 2glox = 0 + 3 glo + 2glox = 0 + 3 Combine like terms: 0 + 3 = 3 glo + 2glox = 3 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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