4m(2)=4(3m-1)

Solution for 4m(2)=4(3m-1) equation:

4m(2)=4(3m-1)

We move all terms to the left:

4m(2)-(4(3m-1))=0

We add all the numbers together, and all the variables

4m^2-(4(3m-1))=0


We calculate terms in parentheses: -(4(3m-1)), so:

4(3m-1)

We multiply parentheses

12m-4

Back to the equation:

-(12m-4)


We get rid of parentheses

4m^2-12m+4=0

a = 4; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·4·4
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{5}}{2*4}=\frac{12-4\sqrt{5}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{5}}{2*4}=\frac{12+4\sqrt{5}}{8}
$