4m(3m+2)=m+2

Solution for 4m(3m+2)=m+2 equation:

4m(3m+2)=m+2

We move all terms to the left:

4m(3m+2)-(m+2)=0

We multiply parentheses

12m^2+8m-(m+2)=0

We get rid of parentheses

12m^2+8m-m-2=0

We add all the numbers together, and all the variables

12m^2+7m-2=0

a = 12; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·12·(-2)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{145}}{2*12}=\frac{-7-\sqrt{145}}{24}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{145}}{2*12}=\frac{-7+\sqrt{145}}{24}
$