4m+2(3-2(m+3))=2m-5

Solution for 4m+2(3-2(m+3))=2m-5 equation:

Simplifying
4m + 2(3 + -2(m + 3)) = 2m + -5

Reorder the terms:
4m + 2(3 + -2(3 + m)) = 2m + -5
4m + 2(3 + (3 * -2 + m * -2)) = 2m + -5
4m + 2(3 + (-6 + -2m)) = 2m + -5

Combine like terms: 3 + -6 = -3
4m + 2(-3 + -2m) = 2m + -5
4m + (-3 * 2 + -2m * 2) = 2m + -5
4m + (-6 + -4m) = 2m + -5

Reorder the terms:
-6 + 4m + -4m = 2m + -5

Combine like terms: 4m + -4m = 0
-6 + 0 = 2m + -5
-6 = 2m + -5

Reorder the terms:
-6 = -5 + 2m

Solving
-6 = -5 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-6 + -2m = -5 + 2m + -2m

Combine like terms: 2m + -2m = 0
-6 + -2m = -5 + 0
-6 + -2m = -5

Add '6' to each side of the equation.
-6 + 6 + -2m = -5 + 6

Combine like terms: -6 + 6 = 0
0 + -2m = -5 + 6
-2m = -5 + 6

Combine like terms: -5 + 6 = 1
-2m = 1

Divide each side by '-2'.
m = -0.5

Simplifying
m = -0.5