4m+20=3(15+m)

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Solution for 4m+20=3(15+m) equation: 



4m+20=3(15+m)

We move all terms to the left:

4m+20-(3(15+m))=0

We add all the numbers together, and all the variables

4m-(3(m+15))+20=0



We calculate terms in parentheses: -(3(m+15)), so:

3(m+15)

We multiply parentheses

3m+45

Back to the equation:

-(3m+45)



We get rid of parentheses

4m-3m-45+20=0

We add all the numbers together, and all the variables

m-25=0

We move all terms containing m to the left, all other terms to the right

m=25

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