4m+2m(m+1)=9m+5

Solution for 4m+2m(m+1)=9m+5 equation:

4m+2m(m+1)=9m+5

We move all terms to the left:

4m+2m(m+1)-(9m+5)=0

We multiply parentheses

2m^2+4m+2m-(9m+5)=0

We get rid of parentheses

2m^2+4m+2m-9m-5=0

We add all the numbers together, and all the variables

2m^2-3m-5=0

a = 2; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·2·(-5)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*2}=\frac{-4}{4}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*2}=\frac{10}{4}
=2+1/2
$