4m+3+m-7=3(6m+1)-(7-m)

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Solution for 4m+3+m-7=3(6m+1)-(7-m) equation: 



4m+3+m-7=3(6m+1)-(7-m)

We move all terms to the left:

4m+3+m-7-(3(6m+1)-(7-m))=0

We add all the numbers together, and all the variables

4m+m-(3(6m+1)-(-1m+7))+3-7=0

We add all the numbers together, and all the variables

5m-(3(6m+1)-(-1m+7))-4=0



We calculate terms in parentheses: -(3(6m+1)-(-1m+7)), so:

3(6m+1)-(-1m+7)

We multiply parentheses

18m-(-1m+7)+3

We get rid of parentheses

18m+1m-7+3

We add all the numbers together, and all the variables

19m-4

Back to the equation:

-(19m-4)



We get rid of parentheses

5m-19m+4-4=0

We add all the numbers together, and all the variables

-14m=0

m=0/-14

m=0

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