4m+3+m-7=3(6m+1)-(7-m)

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Solution for 4m+3+m-7=3(6m+1)-(7-m) equation:



4m+3+m-7=3(6m+1)-(7-m)
We move all terms to the left:
4m+3+m-7-(3(6m+1)-(7-m))=0
We add all the numbers together, and all the variables
4m+m-(3(6m+1)-(-1m+7))+3-7=0
We add all the numbers together, and all the variables
5m-(3(6m+1)-(-1m+7))-4=0
We calculate terms in parentheses: -(3(6m+1)-(-1m+7)), so:
3(6m+1)-(-1m+7)
We multiply parentheses
18m-(-1m+7)+3
We get rid of parentheses
18m+1m-7+3
We add all the numbers together, and all the variables
19m-4
Back to the equation:
-(19m-4)
We get rid of parentheses
5m-19m+4-4=0
We add all the numbers together, and all the variables
-14m=0
m=0/-14
m=0

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