4m+3=m+2(m+7)

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Solution for 4m+3=m+2(m+7) equation: 



4m+3=m+2(m+7)

We move all terms to the left:

4m+3-(m+2(m+7))=0



We calculate terms in parentheses: -(m+2(m+7)), so:

m+2(m+7)

We multiply parentheses

m+2m+14

We add all the numbers together, and all the variables

3m+14

Back to the equation:

-(3m+14)



We get rid of parentheses

4m-3m-14+3=0

We add all the numbers together, and all the variables

m-11=0

We move all terms containing m to the left, all other terms to the right

m=11

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